If z and 1/z are the zeros of the polynominal 4x^2-2x+(k-4),find the value of k.

Open in App

Solution

Let the given polynomial be p(x) = 4x² − 2x +(k − 4)
Given z and 1/z are zeros of the given polynomial
Product of zeroes = (c/a)
That is ( z ×1/z) = (k − 4)/4
⇒ 1 = (k − 4)/4
⇒ 4 = (k − 4)
∴ k = 8

Suggest Corrections

Similar questions

x = \frac{y}{2} = z, \frac{x - 2}{- 2} = \frac{y - 4}{4} = \frac{z - 2}{- 1}

4 x = \frac{y + h}{1} = \frac{- 9 z + k}{- 2}

(h + k) =

| z | < \frac{1}{2}

4 | (1 + i) z^{3} + i z | < k

k

\frac{2 - x}{3} = \frac{2 y - 3}{3 k} = \frac{z - 4}{2}

\frac{2 - 2 x}{5 k} = \frac{y + 4}{2} = \frac{5 - z}{4}

k

k

\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{4}

\frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1}

The value of
$k$ such that $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$
lies in the plane $2 x - 4 y + z = 7$ is

Join BYJU'S Learning Program