CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
230
You visited us 230 times! Enjoying our articles? Unlock Full Access!
Question

If z be a complex number satisfying z4+z3+2z2+z+1=0 then |z| is

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1
z4+z3+2z2+z+1=0
[z4+2z2+1]+[z3+z]=0
[z2+1][z2+1+z]=0
z2+1=0z=±i
|z|=1
or
z2+z+1=0
z=1±142=1±3i2
|z|=14+34=1
|z|=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Representation and Trigonometric Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon