If z be any complex number and if z2+az+b=0 has roots both of which has unit modulus, then
A
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B
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C
arg(b) = 2 arg (a)
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D
None of these
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Solution
The correct option is C arg(b) = 2 arg (a) Let z1,z2 be the roots of z2+az+b=0 Let z1=cisα,z2=cisβand z1+z2=−a,z1z2=b ∴|b|=1,|z1+z2|≤|z1|+|z2|⟹|a|≤2 arg (−a) = α+β2⟹π+arg(a)=α+β2 α+β=2π+2arg(a) ⟹α+β=2arg(a) ⟹arg(b)=2arg(a)