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Question

If z=1+2icosθ4+3isinθ, where θ(0,π2), then which of the following is/are INCORRECT?

A
there exist one value of θ for which Re(z)=0
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B
there exist 2 values of θ for which Re(z)=0
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C
there exist one value of θ for which Im(z)=0
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D
there exist 2 values of θ for which Im(z)=0
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Solution

The correct options are
A there exist one value of θ for which Re(z)=0
B there exist 2 values of θ for which Re(z)=0
D there exist 2 values of θ for which Im(z)=0
Given : z=1+2icosθ4+3isinθ
Now,
z=1+2icosθ4+3isinθ×43isinθ43isinθz=(4+6sinθcosθ)+i(8cosθ3sinθ)16+9sin2θ

When Re(z)=0, then
4+6sinθcosθ16+9sin2θ=04+3sin2θ=0sin2θ=43
Therefore Re(z)=0 not possible for any θ(0,π2)

When Im(z)=0, then
8cosθ3sinθ16+9sin2θ=08cosθ3sinθ=0tanθ=83
Therefore there exist 1 value of θ(0,π2)

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