If z=45(z+10), then z = ?
(a) 40
(b) 20
(c) 10
(d) 60
z=45(z+10)⇒ 5z=4z+40⇒ 5z−4z=40⇒z=40
Minimum z = x + 2y subject to x ≤ 20, y ≥ 10, x ≥ 0, y ≥ 0
If the sum of first 10 natural numbers is S1 and that of first 10 whole numbers is S2 . Then S1−S2 is