Question

If $z$ = $\frac{x}{y}$-$\frac{y}{x}$
then, match the following column.

• A. $\frac{-3}{2}$
• B. $\frac{3}{2}$
• C. 0.0
• D. $\frac{-8}{3}$

Answer 1

Here, given as $z$ = $\frac{x}{y}$-$\frac{y}{x}$
i.) If x = -6 and y = 3
here putting the value of $x$ &$y$,
we get $z$ = $\frac{-6}{3}$-$\frac{3}{6}$
$\Rightarrow$$z$ = $\frac{-6}{3}$-$\frac{3}{6}$ =$2$ - $\frac{1}{2}$=$\frac{-3}{2}$

ii.) If x = 5 and y = -10
here putting the value of $x$ &$y$,
we get $z$ = $\frac{5}{-10}$-$\frac{10}{-5}$
$\Rightarrow$$z$ = -$\frac{1}{2}$+$\frac{2}{1}$ =$2$ - $\frac{1}{2}$= $\frac{3}{2}$

iii.) If x = -4 and y = -4
here putting the value of $x$ &$y$,
we get $z$ = $\frac{-4}{-4}$ - $\frac{-4}{-4}$
$\Rightarrow$$z$ = $1$-$1$ = 0

iv.) If x = 3 and y = 9
here putting the value of $x$ &$y$,
we get $z$ = $\frac{3}{9}$ - $\frac{9}{3}$
$\Rightarrow$$z$ = $\frac{3}{9}$-$\frac{9}{3}$ =$\frac{1}{3}$-$\frac{3}{1}$=$\frac{-8}{3}$