If z - i i i - where i -1- then - z - is equal to-A- e- - 2B- e-C- NoneD- 1

The correct option is D i = e^iπ/2 Then i^i = e^iπ/2^i = e^ π/2 So |z| = 1 ...

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Properties of Cube Root of a Complex Number

If z = i i i ...

Question

If $z$ = $(i)^{(i)^{(i)}}$ , where i = $\sqrt{- 1}$ , then |z| is equal to:

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Solution

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Similar questions

If $z = (i)^{i}$ , where $i = \sqrt{- 1}$ , then Re(z) is:

If $z = i^{i}$ ,where i = $\sqrt{- 1}$ , then Re(z) is

z = (i)^{(i)^{(i)}}

i = \sqrt{- 1}

z = (i)^{(i)^{(i)}}

i = \sqrt{- 1}

z

z = (1 - i)^{- i}

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