If z is a complex number satisfying z−12=i(9−2¯¯¯z), then the value of z+¯¯¯z is
A
10
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B
4
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C
6
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D
8
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Solution
The correct option is B4 Given equation is z−12=i(9−2¯¯¯z)
Let z=a+ib
Now, z−12=i(9−2¯¯¯z)⇒z+2i¯¯¯z=12+9i⇒(a+ib)+2i(a−ib)=12+9i⇒(a+2b)+i(b+2a)=12+9i⇒a+2b=12,b+2a=9⇒a=2,b=5⇒z=2+5i∴z+¯¯¯z=2Re(z)=4