If z is a complex number such that ∣∣∣z−3iz+3i∣∣∣=1 then z lies in
A
the real axis
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B
the line Im(z)=3
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C
a cricle
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D
none of these
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Solution
The correct option is D the real axis ∣∣∣z−3iz+3i∣∣∣=1⇒z−3iz+3i=cosA+isinA⇒2z−6i=cosA+isinA+1cosA+isinA−1⇒z=3i(1+cosA+isinA1−cosA−isinA)=3i⎛⎜
⎜
⎜⎝2cos2A2+2icosA2sinA22sin2A2−2icosA2sinA2⎞⎟
⎟
⎟⎠⇒z=3icotA2⎛⎜
⎜
⎜⎝cosA2+isinA2−icosA2+sinA2⎞⎟
⎟
⎟⎠=3i2cotA2⎛⎜
⎜
⎜⎝cosA2+isinA2cosA2+isinA2⎞⎟
⎟
⎟⎠⇒z=−3cotA2 Therefore z lies on x axis. Ans: A