If $z, i z$ and $z + i z$ are the vertices of a triangle whose area is 2 units, then the value of $| z |$ is

-2

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Solution

The correct option is B 2
$A r e a o f t h e t r i a n g l e = \frac{1}{2} | z |^{2} ∵ \frac{1}{2} | z |^{2} = 2 \Rightarrow | z |^{2} = 4 \Rightarrow | z | = 2.$

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