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B
Im (z) =0
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C
Re(z) = Im(z) =0
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D
Im(z) = Re(z)
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Solution
The correct option is A Re (z) =0 Let z=reiθ Then z+¯z=0 ⇒reiθ+re−iθ=0 ⇒r(eiθ+e−iθ)=0 Since r≠0, we have eiθ+e−iθ=0 cosθ+isinθ+(cosθ−isinθ)=0 (2cosθ)=0 cosθ=0 Thus Re(z)=0 Hence, z is purely imaginary.