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Question

If z satisfies the equation |z| -z=1+2i, then z is equal to

A
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B
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C
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D
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Solution

The correct option is B
Let z = x + iy
|z|z=1+2i
x2+y2(x+iy)=1+2i
(x2+y2x)+i(y)=1+2i
x2+y2x=1 and y=2
Ify=2,x2+4x=1
x2+4=(1+x)2
2x=3;x=32
z=x+iy=322i

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