If z=sinθ+i(cosθ−1),i2=−1 is a purely real as well as a purely imaginary number, then the number of value(s) of θ∈[0,4π] is
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Solution
Given : z=sinθ+i(cosθ−1)
This is a purely real as well as a purely imaginary number, so Re(z)=0,Im(z)=0 ⇒sinθ=0⇒θ=0,π,2π,3π,4π
And ⇒cosθ−1=0⇒cosθ=1⇒θ=0,2π,4π
From (1) and (2), we get θ=0,2π,4π