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Question

If z=sinθ+i(cosθ1),i2=1 is a purely real as well as a purely imaginary number, then the number of value(s) of θ[0,4π] is

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Solution

Given : z=sinθ+i(cosθ1)
This is a purely real as well as a purely imaginary number, so
Re(z)=0, Im(z)=0
sinθ=0θ=0,π,2π,3π,4π
And
cosθ1=0cosθ=1θ=0,2π,4π
From (1) and (2), we get
θ=0,2π,4π

Hence, the number of values of θ[0,4π] is 3.

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