If z=√2−i√2 is rotated through an angle 45° in the anti-clockwise direction about the origin, then the coordinates of its new position are [Kerala (Engg.) 2005]
A
(2, 0)
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B
(√2,√2)
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C
(√2,−√2)
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D
(√2,0
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E
(4, 0)
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Solution
The correct option is D(√2,0 z=√2−i√2
Here, θ=tan−1=(−√2√2)=tan−1(−1)=135o
Now, rotate z in opposite direction with 45° angle