If Z-x tan-1y-x-xex-y then x2-2z- x2-2xy-2z- x- y-y2-2z- y2-

The correct option is D 0 Z is an homogeneous equation of degree n=1 x^2∂^2 z/∂ x^2+2xy∂ ^2z/∂ x∂ y+y^2∂ ^2z/∂ y^2=n (n 1)Z =0 ...

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Differentiation of Inverse Trigonometric Functions

If Z=x tan-...

Question

If $Z = x {tan}^{- 1} (\frac{y}{x}) + x e^{x / y}$

then $x^{2} \frac{\partial^{2} z}{\partial x^{2}} + 2 x y \frac{\partial^{2} z}{\partial x \partial y} + y^{2} \frac{\partial^{2} z}{\partial y^{2}} = ?$

2 z

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z

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3 z

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0

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Solution

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Similar questions

I

z = 3 x^{3} sin \frac{y}{x} + (x^{3} + y^{3}) e^{y / x}

x^{2} \frac{\partial^{2} z}{\partial x^{2}} + y^{2} \frac{\partial^{2} z}{\partial y^{2}} + 2 x y \frac{\partial^{2} z}{\partial x \partial y} = ?

z = a x^{2} + 2 h x y + b y^{2}

x^{2} \frac{\partial^{2} z}{\partial x^{2}} + 2 x y \frac{\partial^{2} z}{\partial x \partial y} + y^{2} \frac{\partial^{2} z}{\partial y^{2}} = ?

x + y + z = x y z

\frac{2 x}{1 - x^{2}} + \frac{2 y}{1 - y^{2}} + \frac{2 z}{1 - z^{2}} = \frac{2 x}{1 - x^{2}} \cdot \frac{2 y}{1 - y^{2}} \cdot \frac{2 z}{1 - z^{2}}

Z = log (\frac{x^{2} + y^{2}}{x y})

\frac{\partial^{2} z}{\partial y^{2}} - \frac{\partial^{2} z}{\partial x^{2}} = 0

F = x^{2} y z - 2 x z^{3} + x z^{2}

\frac{\partial^{2} F}{\partial x \partial y}

(1, 0, - 3)

x^{2} + y^{2} + 2 z^{2} = 4 x - 2 z + 2 y z - 5

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