1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Properties of Modulus
If z = x + iy...
Question
If z = x + iy and |z 1 + 2i | = | z + 1 2i |,
then the locus of z is
A
circle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
parabola
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
straight line
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
straight line
We know that
z
=
x
+
i
y
⇒
|
z
−
1
+
2
i
|
=
|
z
+
1
−
2
i
|
,
locus of
x
=
?
⇒
|
x
+
i
y
−
1
+
2
i
|
=
|
x
+
i
y
+
1
−
2
i
|
⇒
|
(
x
−
1
)
+
i
(
y
+
2
)
|
=
|
(
x
+
1
)
+
i
(
y
−
2
)
|
⇒
√
(
x
−
1
)
2
+
(
y
+
2
)
2
=
√
(
x
+
1
)
2
+
(
y
−
2
)
2
⇒
x
2
−
2
x
+
1
+
y
2
+
4
y
+
4
=
x
2
+
2
x
+
1
+
y
2
−
4
y
+
4
⇒
−
2
x
+
4
y
+
5
=
2
x
−
4
y
+
5
⇒
4
x
=
8
y
⇒
x
=
2
y
∴
x
−
2
y
=
0
∴
The locus of
z
is a straight line.
Hence, the answer straight line.
Suggest Corrections
0
Similar questions
Q.
The locus of the point
z
=
x
+
i
y
satisfying
∣
∣
∣
z
−
2
i
z
+
2
i
∣
∣
∣
=
1
is
Q.
If
z
=
x
+
i
y
,
|
z
|
=
1
and
ω
=
(
1
−
z
)
2
1
−
z
2
, then the locus of
ω
is equivalent to
Q.
The locus of z satisfying the inequality
|
z
+
2
i
2
z
+
i
|
<
1
, where
z
=
x
+
i
y
, is
Q.
If
|
z
−
2
i
|
+
|
z
−
2
|
≥
|
|
z
|
−
|
z
−
2
−
2
i
|
|
, then locus of
z
is
Q.
If |z + 2i| = |z – 2i|, then the locus of z is ____________.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Properties of Modulus
MATHEMATICS
Watch in App
Explore more
Properties of Modulus
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app