If z - x - iy is a complex number such that - z -Re i z-1- then the locus of z isA- y2-1-2 xB- y 2-2 x -1C- x2-1-2 yD- x2-2 y-1

The correct option is C x^2=1 2y z= x + iy iz= y+ix Given, |z|=Re(iz)+1 ⇒√(x^2+y^2)= y+1 ⇒ x^2+y^2=y^2 2y+1 ⇒ x^2=1 2y ...

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Coordinates of a Point in Space

If z = x + iy...

Question

If z = x+ iy is a complex number such that |z| = Re(iz)+1, then the locus of z is

$y^{2} = 1 - 2 x$

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$x^{2} = 2 y - 1$

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$y^{2} = 2 x - 1$

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$x^{2} = 1 - 2 y$

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Solution

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