You visited us 2 times! Enjoying our articles? Unlock Full Access!

Modulus of a Complex Number

If z = x + ...

Question

If $z = x + i y$ satisfies $a m p (z - 1) = a m p (z + 3)$ , then the value of $(x - 1) : y$ is equal to

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

does not exist

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C does not exist
$z = x + i y;$ $a m p (z - 1) = a m p (z + 3)$
Value of $(x - 1) : y$
The principle value of $a r g$ $z$ is denoted by $a r g$ $z$ or $a m p$ $z .$
( amplitude or argument of z )
$\Rightarrow a m p (z = 1) - a m p (z + 3) = 0$
$\Rightarrow a m p [\frac{z - 1}{z + 3}] = 0$
Hence, the answer is it does not exist.

Suggest Corrections

Similar questions

z = x + i y

(z - 1) = a m p (z + 3 i)

(x - 1) : y

z = \frac{{(\sqrt{3} + i)}^{17}}{{(1 - i)}^{50}}

a m p (z)

a m p (\frac{z - 1}{z + 1}) = \frac{π}{3}

a m p \frac{z - 1}{z + 1} = \frac{π}{3}

z

z = x + i y

(z - 1)

(z + 3 i)

(x - 1) : y

Join BYJU'S Learning Program