If $Z = x + j y$ where $x, y$ are real when the value of $| e^{i z} |$ is

1

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e^{\sqrt{x^{2} + y^{2}}}

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e^{y}

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e^{- y}

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Solution

The correct option is D $e^{- y}$
$| e^{i z} | = | e^{i (x + j y)} | = | e^{i x - y} | = | e^{- y} | e^{j x} | = e^{- y}$
$[∵ | Z_{1} Z_{2} | = | Z_{1} | . | Z_{2} |]$
( $∵ | e^{j x} | = | c o s x + j s i n x | = 1$ ) (Using Euler notation)

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