If z1 and z2 are two complex numbers such that z 1- z 2 and z1-z2- then show that z 1- z 2-

Let nbsp; theta;1 nbsp;be the arg(z1) and nbsp; theta;2 nbsp;be the nbsp;arg(z2). It is given that nbsp;z1=z2 nbsp;and arg(z1) + arg(z2) = ...

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If z1 and z2 ...

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If z₁ and z₂ are two complex numbers such that $|z_{1}| = |z_{2}|$ and arg(z₁) + arg(z₂) = $π$ , then show that $z_{1} = - \bar{z_{2}}$ .

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$If z_{1} and z_{2}$ are two complex numbers such that $| z_{1} | = | z_{2} | and (z) + a r g (z_{2}) = π, then show that z_{1} = -_{2} .$

z_{1}

z_{2}

z_{1} \neq z_{2}

| z_{1} | = | z_{2} |

\frac{z_{1} + z_{2}}{z_{1} - z_{2}}

z_{1}

z_{2}

| z_{1} | = | z_{2} | + | z_{1} - z_{2} |

arg (z_{1}) - arg (z_{2})

z_{1}

z_{2}

| z_{1} - z_{2} | = | | z_{1} | - | z_{2} | |

arg (z_{1}) - arg (z_{2}) =

z_{1}

z_{2}

| z_{1} | = | z_{2} |

a r g z_{1} + a r g z_{2} = π

z_{1}

z_{2}

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