If Zeba were younger by $5$ years than she really is, then the square of her age (in years) would have been $11$ more than $5$ times her actual age. What is her age now?

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Solution

Let age of zeba be $x$ years
then
$(x - 5) ² = 11 + 5 x$
$x ² + 25 - 10 x = 11 + 5 x$
$x ² - 15 x + 14 = 0$
$x ² - 14 x - x + 14 = 0$
$x (x - 14) - 1 (x - 14) = 0$
$x = 1$ or $x = 14$
Since, her age will be $14$ years because if she was $1$ years old then $5$ years younger cannot happen

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Question 1(a)

Answer the following:

Take Sarita’s present age to be y years.

(i) What will be her age 5 years from now?

(ii) What was her age 3 years back?

(iii) Sarita’s grandfather is 6 times her age. What is the age of her grandfather?

(iv) Grandmother is 2 years younger than grandfather. What is grandmother’s age?

(v) Sarita’s father’s age is 5 years more than 3 times Sarita’s age. What is her father’s age?

Answer the following:

Take Sarita’s present age to be $y$ years.

(i) What will be her age $5$ years from now?

(ii) What was her age $3$ years back?

(iii) Sarita’s grandfather is $6$ times her age. What is the age of her grandfather?

(iv) Grandmother is $2$ years younger than grandfather. What is grandmother’s age?

(v) Sarita’s father’s age is $5$ years more than $3$ times Sarita’s age. What is her father’s age?

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5

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