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Byju's Answer
Standard IX
Mathematics
Addition of Polynomials
ii 8 x-7 y=11...
Question
(ii) 8x − 7y = 11; 7x − 8y = 4
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Solution
8
x
-
7
y
=
11
.
.
.
.
(
i
)
7
x
-
8
y
=
4
.
.
.
.
(
ii
)
Adding
eq
(
i
)
and
(
ii
)
,
we get:
8
x
-
7
y
=
11
+
7
x
-
8
y
=
4
15
x
-
15
y
=
15
⇒
15
x
-
y
=
15
⇒
x
-
y
=
1
Subtracting
eq
(
ii
)
from
(
i
)
,
we get:
8
x
-
7
y
=
11
7
x
-
8
y
=
4
-
+
-
x
+
y
=
7
∴
x
+
y
=
7
,
x
-
y
=
1
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0
Similar questions
Q.
Find the values of
(
x
+
y
)
and
(
x
−
y
)
without actually solving for
x
and
y
.
8
x
−
7
y
=
11
;
7
x
−
8
y
=
4
Q.
Simplify :
i)
−
14
x
8
y
5
+
21
x
10
y
−
28
x
7
y
6
7
x
7
y
8
ii)
15
a
4
x
8
−
30
a
7
x
5
−
45
a
6
x
6
20
a
14
x
5
iii)
−
60
x
4
a
5
−
75
x
3
a
6
+
8
x
5
a
4
−
20
x
8
a
4
Q.
The value of
x
2
−
y
2
, if
7
x
+
8
y
=
5
and
8
x
+
7
y
=
10
will be
Q.
The equation of the parabola with focus (0, 0) and directrix x + y = 4 is
(a) x
2
+ y
2
− 2xy + 8x + 8y − 16 = 0
(b) x
2
+ y
2
− 2xy + 8x + 8y = 0
(c) x
2
+ y
2
+ 8x + 8y − 16 = 0
(d) x
2
− y
2
+ 8x + 8y − 16 = 0
