Question

Question 13 (ii)
A dice is thrown once. Find the probability of getting a number lying between 2 and 6.

Answer 1

Total number of outcomes of throwing a dice = 6
On a dice, the number lying between 2 and 6 are 3, 4, and 5.
Therefore, the number of favourable outcomes = 3

Hence, P (getting a number lying between 2 and 6)

$=\frac{Favourableoutcomes}{Totalnumberofoutcomes}=\frac{3}{6}=\frac{1}{2}$