(ii) A2 - Zero
Total resistance = (4.5×4.54.5+4.5)=2.25Ω
Therefore, total current = 4.52.25=2A
And since bulb 1 and bulb 3 are identical, 1 A of current will flow through each.
A1 shows 1 ampere, A2 shows zero, A3 shows 1 ampere and A shows 2 amperes.