Question 10 (ii) CD and GH are respectively the bisectors of angleACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. If ΔABC∼ΔFEG, Show that (ii)ΔDCB∼ΔHGE
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Solution
(ii) In ΔDCBandΔHGE, ∠DCB=∠HGE (Halves of ∠BCA and ∠FGE) ∠B=∠E (Because it is given that ΔABC∼ΔFEG) ∴ΔDCB∼ΔHGE (By AAA similarity criterion)