Question

Question 2 (ii)
Choose the correct option and justify your choice.
(ii) $\frac{1-ta{n}^2{45}^0}{1+ta{n}^2{45}^0}=$
(A) $tan{90}^{\circ }$
(B) 1
(C) $sin{45}^{\circ }$
(D) 0

Answer 1

(ii) Option (D) is correct.
$\frac{(1-ta{n}^2{45}^{\circ })}{(1+ta{n}^2{45}^{\circ })}=\frac{(1-1^2)}{(1+1^2)}=\frac{0}{2}=0$