Factorise
$63 a^{2} - 112 b^{2}$

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Solution

$63 a^{2} - 112 b^{2}$
$= 7 (9 a^{2} - 16 b^{2}) (Taking 7 as common)$
$= 7 [(3 a)^{2} - (4 b)^{2}]$
$= 7 (3 a + 4 b) (3 a - 4 b) [a^{2} - b^{2} = (a - b) (a + b)]$

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Question 2(ii)

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$63 a^{2} - 112 b^{2}$

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