Question 1 (ii) Find the area of the triangle whose vertices are: (ii) (-5, -1), (3, -5), (5, 2)
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Solution
Let (x1,y1)=(−5,−1), (x2,y2)=(3,−5) and (x3,y3)=(5,2), Area of a triangle =12{x1(y2−y3)+x2(y3−y1)+x3(y1−y2)} =12[−5{(−5)−(2)}+3(2−(−1))+5{−1−(−5)}] = 12{35+9+20} = 32 square units