Find the following squares by using identities:
$(x y + 3 z)^{2}$

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Solution

Since, we know that $(a + b)^{2} = a^{2} + 2 a b + b^{2}$
Substitute $a = x y, b = 3 z$ , we get
( $x y + 3 z)^{2} = (x y)^{2} + 2 \times x y \times 3 z + (3 z)^{2}$
$∴ (x y + 3 z)^{2} = x^{2} y^{2} + 6 x y z + 9 z^{2}$

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