Question 5 (ii) Find the number of terms in each of the following A.P. (ii) 18,1512,13……−47
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Solution
(ii) ForthisA.P,a=18d=a2−a1=1512−18d=31−362=−52LettherearentermsinthisA.P.an=−47an=a+(n−1)d−47=18+(n−1)(−52)−47−18=(n−1)(−52)−65=(n−1)(−52)(n−1)=−130−5(n−1)=26n=27Therefore,thisgivenA.P.has27termsinit.