Ii Find the product of -22-11 and -21-11-

Given, 22/11 and 21/11 ∴ Product of rational numbers = Product of numerators/Product of denominators = ( 22) × ( 21)/11 × 11 = 462/121 = 462 ÷ 11/121 ÷ 11 = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Multiplication and Division of Rational Numbers

ii Find the p...

Question

Question 80 (ii)

Find the product of $\frac{- 22}{11}$ and $\frac{- 21}{11}$ .

Open in App

Solution

Given, $\frac{- 22}{11}$ and $\frac{- 21}{11}$
$∴$ Product of rational numbers = $\frac{P r o d u c t o f n u m e r a t o r s}{P r o d u c t o f d e n o m i n a t o r s} = \frac{(- 22) \times (- 21)}{11 \times 11} = \frac{462}{121} = \frac{462 \div 11}{121 \div 11} = \frac{42}{11}$

Suggest Corrections

Similar questions

Q. Find

\frac{3}{7} + (\frac{- 6}{11}) + (\frac{- 8}{21}) + (\frac{5}{22})

Q. Among

_{10} A^{20},_{11} B^{21},_{10} C^{22}

and

_{11} D^{22}

, the isobaric combination is:

Q. If A = [a_ij] =

[\begin{matrix} 2 & 3 & - 5 \\ 1 & 4 & 9 \\ 0 & 7 & - 2 \end{matrix}]

and B = [b_ij] =

[\begin{matrix} 2 & - 1 \\ - 3 & 4 \\ 1 & 2 \end{matrix}]

then find (i) a₂₂ + b₂₁ (ii) a₁₁ b₁₁ + a₂₂ b₂₂

Q. Question 4(viii)
Find

2 \frac{1}{5} \div 1 \frac{1}{5}

Q. In the above question, a₁₁ C₂₁ + a₁₂ C₂₂ + a₁₃ C₂₃ = __________.

Join BYJU'S Learning Program

Explore more

Multiplication and Division of Rational Numbers

Standard VII Mathematics

Join BYJU'S Learning Program

Question 80 (ii) Find the product of −2211 and −2111.

Given, −2211 and −2111 ∴ Product of rational numbers = Product of numeratorsProduct of denominators=(−22)×(−21)11×11=462121=462÷11121÷11=4211

Question 80 (ii)

Find the product of $\frac{- 22}{11}$ and $\frac{- 21}{11}$ .

Given, $\frac{- 22}{11}$ and $\frac{- 21}{11}$
$∴$ Product of rational numbers = $\frac{P r o d u c t o f n u m e r a t o r s}{P r o d u c t o f d e n o m i n a t o r s} = \frac{(- 22) \times (- 21)}{11 \times 11} = \frac{462}{121} = \frac{462 \div 11}{121 \div 11} = \frac{42}{11}$