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Question

Question 1 (ii)
Find the sum of the following APs
(ii) − 37, − 33, − 29 ,…, to 12 terms

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Solution

(ii) 37,33,29,,to 12 termsFor this A.P.,a=37d=a2a1=(33)(37)=33+37=4n=12We know that,Sn=n2[2a+(n1)d]S12=122[2(37)+(121)×4]=6[74+11×4]=6[74+44]=6(30)=180

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