Question 12 (ii)
Find the values of the angles x, y and z in each of the following:
40∘+x+25∘=180∘ [Angles on straight line]⇒65∘+x=180⇒x=180∘−65∘=115∘Now, 40∘+y=180∘ [Linear pair]⇒y=180∘−40∘=140∘ ....(i)Also 40∘+y=180∘ [Linear pair]⇒140∘+z=180∘ [From eq.(i)]⇒z=180∘−140∘=40∘Thus, x=115∘,y=140∘ and z=40∘