(ii) 3x2+4x–4
Let f(x)=3x2+4x–4
=3x2+6x–2x–4 [by splitting the middle term]
=(x + 2) (3x – 2)
So, the value of 3x2+4x–4 is zero when x+2=0 or 3x – 2 = 0, i.e., when x=−2 or x=23
so, the zeroes of 3x2+4x–4 are −2 and 23
∴ Sum of zeroes = −2+23=−43
= (−1)[Coefficient of xCoefficient of x2]
And product of zeroes = (−2)(23)=−43
=(−1)2(Constant termCoefficient of x2)
Hence, verified the relations between the zeroes and the coefficients of the polynomial.