ii) Given that, sum of zeroes (S)=218
and product of zeroes ( P)=516
∴ Required quadratic expression, f(x)=x2–Sx+P
=x2–218x+516=16x2−42x+5
Using factorization method = 16x2–40x–2x+5
=8x(2x–5)–1(2x–5)=(2x–5)(8x–1)
Hence, the zeroes of f(x) are 52and18