Question 125 (ii)
If '*' is an operation have, such that for integers a and b. We have a∗b=a×b+(a×a+b×b), then find (−6)∗2
Now, put a = -6 and b = 2 (−6)∗2=(−6×2)+(−6)×(−6)+2×2=−6×2+(36+4)=−12+40=28
Question 126 (i)
If Δ is an operation, such that for integers a and b. We have aΔb=a×b−2×a×b+b×b (−a)×b+b×b, then find 4 Δ (−3) Also, show that 4 Δ (−3) ≠ (−3) Δ 4