Question

Question 1 (ii)
In $\Delta$ ABC, right-angled at B, AB = 24 cm and BC = 7 cm. Determine:
(ii) sin C, cos C

Answer 1

In $\Delta$ ABC, $\angle$B = ${90}^{\circ }$

By applying Pythagoras theorem, we get,
$A{C}^2=A{B}^2+B{C}^2=(24{)}^2+(7{)}^2=(576+49)c{m}^2=625c{m}^2$
$\Rightarrow$ AC = 25
(ii) $sinC=\frac{AB}{AC}=\frac{24}{25}$
$cosC=\frac{BC}{AC}=\frac{7}{25}$