Question 6 (ii) In the given figure, diagonals AC and BD of quadrilateral ABCD intersect at O such thatOB = OD. If AB = CD, then show that: (ii) ar(DCB) = ar(ACB)
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Solution
Let us draw DN⊥AC and BM⊥AC. (ii) We obtained, Area (ΔDOC)=Area(ΔAOB) i.e Area(ΔDOC)+Area(ΔOCB)=Area(ΔAOB)+Area(ΔOCB) (Adding Area (ΔOCB) to both sides) ⇒Area(ΔDCB)=Area(ΔACB)