Question 150 (ii)

In the given figure, PQ = PS and $∠ 1 = ∠ 2$
Is QR = SR? Give reason

Open in App

Solution

PQ = PS [given]
$∠ 1 = ∠ 2$ [given]
PR = PR [ common side ]

By SAS congruence criterion, ΔPQR ≅ ΔPSR

$∴$ QR = SR [by CPCT]

Suggest Corrections

Similar questions

Question 150 (i)

In the given figure, PQ = PS and $∠ 1 = ∠ 2$
Is $Δ P Q R ≅ Δ P S R$ ? Give reason.

P S = Q R, P Q = S R

The diagonal PR of a quadrilateral PQRS bisects the angles P and R, then

P S = Q R = 25 c m, P Q = 18 c m

S R = 32 c m

{PR}^{2} = {PS}^{2} + QR \times ST + {(\frac{QR}{2})}^{2}

{PQ}^{2} = {PS}^{2} - QR \times ST + {(\frac{QR}{2})}^{2}

Join BYJU'S Learning Program