Question 154 (ii)
In the given figure, QS⊥PR, RT⊥PQ and QS = RT Is ∠PQR=∠PRQ? Give reason.
By RHS congruence criterion, ΔQSR≅ΔRTQ
Hence, yes ∠PQR=∠PRQ [by CPCT]
Question 154 (i)
In the given figure, QS⊥PR,RT⊥PQ and QS=RT Is ΔQSR≅ΔRTQ? Give reason.
In the given figure, T is a point on side QR of ΔPQR and S is a point such that RT = ST. Which of the following is true?
In the given figure, RS=QT and QS=RT. Then which of the following options is correct?
In the given figure, RS = QT and QS = RT. Then which of the following options is correct?