Question 112(ii)

In the given figure, show that
EF || GH

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Solution

From the given figure,
$∠ G K L + ∠ L K J = 180^{\circ} \Rightarrow L K J = 180^{\circ} - ∠ G K L = 180^{\circ} - 50^{\circ} = 130^{\circ}$
Now, $∠ A L I = ∠ L K J = 130^{\circ} E F | | G H a s t h e i r c o r r e s p o n d i n g a n g l e s a r e e q u a l .$

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Question 110(i)

In the given figure, examine whether the following pairs of lines are parallel or not.
EF and GH

A B

| |

C D

| |

E F

G H

| |

K L

x

A B | | C D | | E F

G H | | K L,

∠ H K L,

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