Question

Question 3(ii)
Solve the following equation by trial and error method:
3m- 14 = 4

Answer 1

3m-14=4
Putting m=-2 in L.H.S 3(-2)-14=-6-14=-20
$\because$ -20 $\ne$ 4 Therefore, m=-2 is not the solution.
Putting m=-1 in L.H.S 3(-1) -14=-3-14=-17
$\because$ -17 $\ne$ 4 Therefore, m = -1 is not the solution.
Putting m=0 in L.H.S 3(0)-14=0-14=-14
$\because$ -14 $\ne$ 4 Therefore,m=0 is not the solution.
Putting m=1 in L.H.S 3(1)-14=3-14=-11
$\because$ -11 $\ne$ 4 Therefore, m=1 is not the solution.
Putting m=2 in L.H.S 3(2) -14=6-14=-8
$\because$ -8 $\ne$ 4 Therefore, m=2 is not the solution.
Putting m=3 in L.H.S 3(3)-14=9-14=-5
$\because$ -5 $\ne$ 4 Therefore, m=3 is not the solution.
Putting m=5 in L.H.S 3(5)-14=15-14=1
$\because$ 1 $\ne$ 4 Therefore, m=5 is not the solution.
Putting m=6 in L.H.S 3(6)-14=18-14=4
$\because$ 4=4 Therefore, m=6 is the solution.