Question

Question 21(ii)
Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is 12?

Answer 1

Number of total outcomes = 36
When product of the numbers on the top of the dice is 12.
So, the possible ways are (2,6), (3,4),(4,3) adn (6,2).
Number of possible ways = 4
$\therefore$ Required probability $=\frac{4}{36}=\frac{1}{9}$