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Algebraic Identities

ii Using a2-b...

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Question 7(ii)
Using $a^{2} - b^{2} = (a + b) (a - b),$ find
$(1.02)^{2} - (0.98)^{2}$

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Solution

$(1.02)^{2} - (0.98)^{2} = (1.02 + 0.98) (1.02 - 0.98)$
$[U s i n g i d e n t i t y (a - b) (a + b) = a^{2} - b^{2}]$
$= 2.00 \times 0.04 = 0.08$

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Q. Question 7(ii)
Using

a^{2} - b^{2} = (a + b) (a - b),

(1.02)^{2} - (0.98)^{2}

Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
${1.02}^{2} - {0.98}^{2}$

Using a²-b²=(a+b)(a-b) find:

i. 51² - 49²

ii. (1.02)² - (0.98)²

Using the identity a^{2} - b^{2} = (a + b) (a - b)

Find the value of (1.02)^{2} - (0.98)^{2} .

Using a²− b² = (a + b) (a − b), find

(i) 51² − 49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² − 7.9²

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Algebraic Identities

Standard VIII Mathematics

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