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Question

Question 2 (ii)
Verify that each of the following is an AP and then write its next three terms.
5,143,133,4,

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Solution

Here, a1=5, a2=143, a3=133 and a4=4

a2a1=1435=14153=13,
a3a2=133143=13,
a4a3=4133=12133=13

a2a1=a3a2=a4a3

Since the difference between successive terms are same, it forms an AP.
The next three terms are,
a5=a1+4d=5+4(13)=543=113
[ an=a1+(n1)d]
a6=a1+5d=5+5(13)=553=103
a7=a1+6d=5+6(13)=52=3

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