Question 9 (ii)

Which is greater in each of the following:
$\frac{- 5}{6}, \frac{- 4}{3}$

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Solution

$\frac{- 5 \times 1}{6 \times 1} = \frac{- 5}{6} a n d \frac{- 4 \times 2}{3 \times 2} = \frac{- 8}{6}$
Since, $\frac{- 5}{6}$ > $\frac{- 8}{6}$
Therefore $\frac{- 5}{6}$ > $\frac{- 4}{3}$

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