Question

IIf the H.C.F of $657$ and $963$ is expressible in the form of $657x+963\times (-15)$ then find the value of $x$

Answer 1

First, we have to find the HCF of $657$ and $963$

Now, $657=9\times 63$ and $963=9\times 107$

Since HCF is expressed in the form $657x+963\times (-15)$

So, $657x+963\times (-15)=9$

$\Rightarrow 657x-963\times 15=9$

$\Rightarrow 657x=14445+9$

$\Rightarrow x=\frac{14454}{657}=22$

So, the value of $x$ is $22$