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Byju's Answer
Standard IX
Mathematics
Solving Equations Having the Variable on Both Sides
iii 2 x-3 y-3...
Question
(iii) 2x − 3y − 3 = 7; 4x − 5y − 5 = 10
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Solution
2
x
-
3
y
-
3
=
7
⇒
2
x
-
3
y
=
10
⇒
x
=
10
+
3
y
2
.
.
.
(
i
)
4
x
-
5
y
-
5
=
10
⇒
4
x
-
5
y
=
15
.
.
.
.
(
ii
)
Substituting
eq
(
i
)
in
eq
(
ii
)
,
we
get
:
4
×
10
+
3
y
2
-
5
y
=
15
⇒
20
+
6
y
-
5
y
=
15
⇒
y
=
-
5
Substituting
y
=
-
5
in
eq
(
i
)
,
we
get
:
x
=
10
+
3
×
-
5
2
∴
x
=
-
5
2
Hence
,
x
=
-
5
2
,
y
=
-
5
is
the
solution
of
the
given
equations
.
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Similar questions
Q.
Solve the following equations by substitution method.
2
x
−
3
y
−
3
=
7
;
4
x
−
5
y
−
5
=
10
Q.
State whether True or False:
Factorization of
15
(
2
x
−
y
)
2
−
16
(
2
x
−
y
)
−
15
is
(
6
x
−
3
y
−
5
)
(
10
−
5
y
+
3
)
.
Q.
The three planes 4y + 6z = 5; 2x + 3y + 5z = 5; 6x + 5y + 9z = 10.
Q.
The three planes
4
y
+
6
z
=
5
,
2
x
+
3
y
+
5
z
=
5
,
6
x
+
5
y
+
9
z
=
10
Q.
2
x
+
5
y
=
1
,
2
x
+
3
y
=
3
.
