Question 2 (iii) Choose the correct option and justify your choice. (iii) sin2A = 2sinA is true when A = (A) 0∘ (B) 30∘ (C) 45∘ (D) 60∘
Open in App
Solution
Option (A) is correct. sin 2A = 2 sin A is true when A = 0∘ As sin 2A = sin 0∘ = 0 2 sin A = 2sin 0∘ = 2×0 = 0 Another Method sin 2A = 2sin A cos A ⇒2sin A cos A =2 sin A ⇒ cos A = 1 ⇒ A = 0∘