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Question

Question 2 (iii)
Find the roots of the quadratic equations given in Q.1 above by applying the quadratic formula.
(iii) 4x2+43x+3=0

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Solution

(iii) 4x2+43x+3=0
On comparing this equation with ax2+bx+c=0, we get
a=4,b=43 and c=3
By using quadratic formula, we get
x=b±b24ac2a
x=43±(43)24×4×32×4
x=43±48488
x=43±08
x=438
x=32

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